1.计算每个人的总成绩并排名 select name,sum(score) as allscore from stuscore group by name order by allscore 2.计算每个人的总成绩并排名 select distinct t1.name,t1.stuid,t2.allscore from stuscore t1,( select stuid,sum(score) as allscore from stuscore group by stuid)t2where t1.stuid=t2.stuidorder by t2.allscore desc 3. 计算每个人单科的最高成绩 select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(select stuid,max(score) as maxscore from stuscore group by stuid) t2where t1.stuid=t2.stuid and t1.score=t2.maxscore 4.计算每个人的平均成绩 select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,(select stuid,avg(score) as avgscore from stuscore group by stuid) t2where t1.stuid=t2.stuid 5.列出各门课程成绩最好的学生 select t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,(select subject,max(score) as maxscore from stuscore group by subject) t2where t1.subject=t2.subject and t1.score=t2.maxscore 6.列出各门课程成绩最好的两位学生 select distinct t1.* from stuscore t1 where t1.id in (select top 2 stuscore.id from stuscore where subject = t1.subject order by score desc) order by t1.subject 7.学号 姓名 语文 数学 英语 总分 平均分 select stuid as 学号,name as 姓名,sum(case when subject='语文' then score else 0 end) as 语文,sum(case when subject='数学' then score else 0 end) as 数学,sum(case when subject='英语' then score else 0 end) as 英语,sum(score) as 总分,(sum(score)/count(*)) as 平均分from stuscoregroup by stuid,name order by 总分desc 8.列出各门课程的平均成绩 select subject,avg(score) as avgscore from stuscoregroup by subject 9.列出数学成绩的排名 declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id 1,pm=@idselect * from @tmp select DENSE_RANK () OVER(order by score desc) as row,name,subject,score,stuid from stuscore where subject='数学'order by score desc 10. 列出数学成绩在2-3名的学生 select t3.* from(select top 2 t2.* from (select top 3 name,subject,score,stuid from stuscore where subject='数学'order by score desc) t2 order by t2.score) t3 order by t3.score desc 11. 求出李四的数学成绩的排名 declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id 1,pm=@idselect * from @tmp where name='李四' 12. 课程 不及格 良 优 select subject, (select count(*) from stuscore where score60 and subject=t1.subject) as 不及格,(select count(*wns9778.com,) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,(select count(*) from stuscore where score 80 and subject=t1.subject) as 优from stuscore t1 group by subject 13. 数学:张三(50分),李四(90分),王五(90分),赵六(76分) declare @s varchar(1000)set @s=''select @s =@s ',' name '(' convert(varchar(10),score) '分)' from stuscore where subject='数学' set @s=stuff(@s,1,1,'')print '数学:' @s
学生成绩表(stuscore):
姓名:name |
课程:subject |
分数:score |
学号:stuid |
张三 |
数学 |
89 |
1 |
张三 |
语文 |
80 |
1 |
张三 |
英语 |
70 |
1 |
李四 |
数学 |
90 |
2 |
李四 |
语文 |
70 |
2 |
李四 |
英语 |
80 |
2 |
创建表 ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET ANSI_PADDING ON
GO
CREATE TABLE [dbo].[stuscore](
[name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[subject] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[score] [int] NULL,
[stuid] [int] NULL
) ON [PRIMARY]
GO
SET ANSI_PADDING OFF
问题:
1. 计算每个人的总成绩并排名(要求显示字段:姓名,总成绩)
2. 计算每个人的总成绩并排名(要求显示字段: 学号,姓名,总成绩)
3. 计算每个人单科的最高成绩(要求显示字段: 学号,姓名,课程,最高成绩)
4. 计算每个人的平均成绩(要求显示字段: 学号,姓名,平均成绩)
5. 列出各门课程成绩最好的学生(要求显示字段: 学号,姓名,科目,成绩)
6. 列出各门课程成绩最好的两位学生(要求显示字段: 学号,姓名,科目,成绩)
7. 统计如下:
学号 |
姓名 |
语文 |
数学 |
英语 |
总分 |
平均分 |
8.列出各门课程的平均成绩(要求显示字段:课程,平均成绩)
9.列出数学成绩的排名(要求显示字段:学号,姓名,成绩,排名)
10.列出数学成绩在2-3名的学生(要求显示字段:学号,姓名,科目,成绩)
11.求出李四的数学成绩的排名
12.统计如下:
课程 |
不及格(0-59)个 |
良(60-80)个 |
优(81-100)个 |
13.统计如下:数学:张三(50分),李四(90分),王五(90分),赵六(76分)
答案:
1. 计算每个人的总成绩并排名
select name,sum(score) as allscore from stuscore group by name order by allscore
- 计算每个人的总成绩并排名
select distinct t1.name,t1.stuid,t2.allscore from stuscore t1,
(
select stuid,sum(score) as allscore from stuscore group by stuid
)t2
where t1.stuid=t2.stuid
order by t2.allscore desc
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